Integrand size = 28, antiderivative size = 276 \[ \int \frac {1}{(d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\frac {3 b^2 e}{(b d-a e)^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {b^2}{2 (b d-a e)^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {e^2 (a+b x)}{2 (b d-a e)^3 (d+e x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {3 b e^2 (a+b x)}{(b d-a e)^4 (d+e x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {6 b^2 e^2 (a+b x) \log (a+b x)}{(b d-a e)^5 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {6 b^2 e^2 (a+b x) \log (d+e x)}{(b d-a e)^5 \sqrt {a^2+2 a b x+b^2 x^2}} \]
3*b^2*e/(-a*e+b*d)^4/((b*x+a)^2)^(1/2)-1/2*b^2/(-a*e+b*d)^3/(b*x+a)/((b*x+ a)^2)^(1/2)+1/2*e^2*(b*x+a)/(-a*e+b*d)^3/(e*x+d)^2/((b*x+a)^2)^(1/2)+3*b*e ^2*(b*x+a)/(-a*e+b*d)^4/(e*x+d)/((b*x+a)^2)^(1/2)+6*b^2*e^2*(b*x+a)*ln(b*x +a)/(-a*e+b*d)^5/((b*x+a)^2)^(1/2)-6*b^2*e^2*(b*x+a)*ln(e*x+d)/(-a*e+b*d)^ 5/((b*x+a)^2)^(1/2)
Time = 1.06 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.59 \[ \int \frac {1}{(d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\frac {(a+b x) \left (-b^2 (b d-a e)^2+6 b^2 e (b d-a e) (a+b x)+\frac {e^2 (b d-a e)^2 (a+b x)^2}{(d+e x)^2}+\frac {6 b e^2 (b d-a e) (a+b x)^2}{d+e x}+12 b^2 e^2 (a+b x)^2 \log (a+b x)-12 b^2 e^2 (a+b x)^2 \log (d+e x)\right )}{2 (b d-a e)^5 \left ((a+b x)^2\right )^{3/2}} \]
((a + b*x)*(-(b^2*(b*d - a*e)^2) + 6*b^2*e*(b*d - a*e)*(a + b*x) + (e^2*(b *d - a*e)^2*(a + b*x)^2)/(d + e*x)^2 + (6*b*e^2*(b*d - a*e)*(a + b*x)^2)/( d + e*x) + 12*b^2*e^2*(a + b*x)^2*Log[a + b*x] - 12*b^2*e^2*(a + b*x)^2*Lo g[d + e*x]))/(2*(b*d - a*e)^5*((a + b*x)^2)^(3/2))
Time = 0.35 (sec) , antiderivative size = 169, normalized size of antiderivative = 0.61, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {1102, 27, 54, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {1}{\left (a^2+2 a b x+b^2 x^2\right )^{3/2} (d+e x)^3} \, dx\) |
| \(\Big \downarrow \) 1102 |
| \(\displaystyle \frac {b^3 (a+b x) \int \frac {1}{b^3 (a+b x)^3 (d+e x)^3}dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {(a+b x) \int \frac {1}{(a+b x)^3 (d+e x)^3}dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\) |
| \(\Big \downarrow \) 54 |
| \(\displaystyle \frac {(a+b x) \int \left (\frac {6 e^2 b^3}{(b d-a e)^5 (a+b x)}-\frac {3 e b^3}{(b d-a e)^4 (a+b x)^2}+\frac {b^3}{(b d-a e)^3 (a+b x)^3}-\frac {6 e^3 b^2}{(b d-a e)^5 (d+e x)}-\frac {3 e^3 b}{(b d-a e)^4 (d+e x)^2}-\frac {e^3}{(b d-a e)^3 (d+e x)^3}\right )dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle \frac {(a+b x) \left (\frac {6 b^2 e^2 \log (a+b x)}{(b d-a e)^5}-\frac {6 b^2 e^2 \log (d+e x)}{(b d-a e)^5}+\frac {3 b^2 e}{(a+b x) (b d-a e)^4}-\frac {b^2}{2 (a+b x)^2 (b d-a e)^3}+\frac {3 b e^2}{(d+e x) (b d-a e)^4}+\frac {e^2}{2 (d+e x)^2 (b d-a e)^3}\right )}{\sqrt {a^2+2 a b x+b^2 x^2}}\) |
((a + b*x)*(-1/2*b^2/((b*d - a*e)^3*(a + b*x)^2) + (3*b^2*e)/((b*d - a*e)^ 4*(a + b*x)) + e^2/(2*(b*d - a*e)^3*(d + e*x)^2) + (3*b*e^2)/((b*d - a*e)^ 4*(d + e*x)) + (6*b^2*e^2*Log[a + b*x])/(b*d - a*e)^5 - (6*b^2*e^2*Log[d + e*x])/(b*d - a*e)^5))/Sqrt[a^2 + 2*a*b*x + b^2*x^2]
3.17.3.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[E xpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && ILtQ[m, 0] && IntegerQ[n] && !(IGtQ[n, 0] && LtQ[m + n + 2, 0])
Int[((d_.) + (e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S ymbol] :> Simp[(a + b*x + c*x^2)^FracPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*F racPart[p])) Int[(d + e*x)^m*(b/2 + c*x)^(2*p), x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && EqQ[b^2 - 4*a*c, 0]
Leaf count of result is larger than twice the leaf count of optimal. \(507\) vs. \(2(206)=412\).
Time = 2.61 (sec) , antiderivative size = 508, normalized size of antiderivative = 1.84
| method | result | size |
| default | \(-\frac {\left (48 \ln \left (b x +a \right ) x^{2} a \,b^{3} d \,e^{3}+e^{4} a^{4}-b^{4} d^{4}+8 a \,b^{3} d^{3} e -8 b \,e^{3} d \,a^{3}+24 \ln \left (b x +a \right ) x \,a^{2} b^{2} d \,e^{3}+24 \ln \left (b x +a \right ) x a \,b^{3} d^{2} e^{2}-48 \ln \left (e x +d \right ) x^{2} a \,b^{3} d \,e^{3}-12 \ln \left (e x +d \right ) x^{2} a^{2} b^{2} e^{4}+12 \ln \left (b x +a \right ) b^{4} d^{2} e^{2} x^{2}+4 x \,b^{4} d^{3} e -24 \ln \left (e x +d \right ) x a \,b^{3} d^{2} e^{2}-24 \ln \left (e x +d \right ) a \,b^{3} e^{4} x^{3}-24 \ln \left (e x +d \right ) x \,a^{2} b^{2} d \,e^{3}-12 \ln \left (e x +d \right ) x^{4} b^{4} e^{4}-12 \ln \left (e x +d \right ) x^{2} b^{4} d^{2} e^{2}-24 \ln \left (e x +d \right ) x^{3} b^{4} d \,e^{3}+12 \ln \left (b x +a \right ) x^{2} a^{2} b^{2} e^{4}+24 \ln \left (b x +a \right ) x^{3} a \,b^{3} e^{4}+12 \ln \left (b x +a \right ) b^{4} e^{4} x^{4}-12 x^{3} a \,b^{3} e^{4}+12 x^{3} b^{4} d \,e^{3}-18 x^{2} a^{2} b^{2} e^{4}+18 x^{2} b^{4} d^{2} e^{2}-4 x \,a^{3} b \,e^{4}-12 \ln \left (e x +d \right ) a^{2} b^{2} d^{2} e^{2}+24 \ln \left (b x +a \right ) x^{3} b^{4} d \,e^{3}-24 x \,a^{2} b^{2} d \,e^{3}+24 x a \,b^{3} d^{2} e^{2}+12 \ln \left (b x +a \right ) a^{2} b^{2} d^{2} e^{2}\right ) \left (b x +a \right )}{2 \left (e x +d \right )^{2} \left (a e -b d \right )^{5} \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}\) | \(508\) |
| risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (\frac {6 b^{3} e^{3} x^{3}}{e^{4} a^{4}-4 b \,e^{3} d \,a^{3}+6 b^{2} e^{2} d^{2} a^{2}-4 a \,b^{3} d^{3} e +b^{4} d^{4}}+\frac {9 b^{2} e^{2} \left (a e +b d \right ) x^{2}}{e^{4} a^{4}-4 b \,e^{3} d \,a^{3}+6 b^{2} e^{2} d^{2} a^{2}-4 a \,b^{3} d^{3} e +b^{4} d^{4}}+\frac {2 \left (a^{2} e^{2}+7 a b d e +b^{2} d^{2}\right ) b e x}{e^{4} a^{4}-4 b \,e^{3} d \,a^{3}+6 b^{2} e^{2} d^{2} a^{2}-4 a \,b^{3} d^{3} e +b^{4} d^{4}}-\frac {a^{3} e^{3}-7 a^{2} b d \,e^{2}-7 a \,b^{2} d^{2} e +b^{3} d^{3}}{2 \left (e^{4} a^{4}-4 b \,e^{3} d \,a^{3}+6 b^{2} e^{2} d^{2} a^{2}-4 a \,b^{3} d^{3} e +b^{4} d^{4}\right )}\right )}{\left (b x +a \right )^{3} \left (e x +d \right )^{2}}-\frac {6 \sqrt {\left (b x +a \right )^{2}}\, b^{2} e^{2} \ln \left (b x +a \right )}{\left (b x +a \right ) \left (a^{5} e^{5}-5 a^{4} b d \,e^{4}+10 a^{3} b^{2} d^{2} e^{3}-10 a^{2} b^{3} d^{3} e^{2}+5 a \,b^{4} d^{4} e -b^{5} d^{5}\right )}+\frac {6 \sqrt {\left (b x +a \right )^{2}}\, b^{2} e^{2} \ln \left (-e x -d \right )}{\left (b x +a \right ) \left (a^{5} e^{5}-5 a^{4} b d \,e^{4}+10 a^{3} b^{2} d^{2} e^{3}-10 a^{2} b^{3} d^{3} e^{2}+5 a \,b^{4} d^{4} e -b^{5} d^{5}\right )}\) | \(518\) |
-1/2*(48*ln(b*x+a)*x^2*a*b^3*d*e^3+e^4*a^4-b^4*d^4+8*a*b^3*d^3*e-8*b*e^3*d *a^3+24*ln(b*x+a)*x*a^2*b^2*d*e^3+24*ln(b*x+a)*x*a*b^3*d^2*e^2-48*ln(e*x+d )*x^2*a*b^3*d*e^3-12*ln(e*x+d)*x^2*a^2*b^2*e^4+12*ln(b*x+a)*b^4*d^2*e^2*x^ 2+4*x*b^4*d^3*e-24*ln(e*x+d)*x*a*b^3*d^2*e^2-24*ln(e*x+d)*a*b^3*e^4*x^3-24 *ln(e*x+d)*x*a^2*b^2*d*e^3-12*ln(e*x+d)*x^4*b^4*e^4-12*ln(e*x+d)*x^2*b^4*d ^2*e^2-24*ln(e*x+d)*x^3*b^4*d*e^3+12*ln(b*x+a)*x^2*a^2*b^2*e^4+24*ln(b*x+a )*x^3*a*b^3*e^4+12*ln(b*x+a)*b^4*e^4*x^4-12*x^3*a*b^3*e^4+12*x^3*b^4*d*e^3 -18*x^2*a^2*b^2*e^4+18*x^2*b^4*d^2*e^2-4*x*a^3*b*e^4-12*ln(e*x+d)*a^2*b^2* d^2*e^2+24*ln(b*x+a)*x^3*b^4*d*e^3-24*x*a^2*b^2*d*e^3+24*x*a*b^3*d^2*e^2+1 2*ln(b*x+a)*a^2*b^2*d^2*e^2)*(b*x+a)/(e*x+d)^2/(a*e-b*d)^5/((b*x+a)^2)^(3/ 2)
Leaf count of result is larger than twice the leaf count of optimal. 760 vs. \(2 (206) = 412\).
Time = 0.28 (sec) , antiderivative size = 760, normalized size of antiderivative = 2.75 \[ \int \frac {1}{(d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=-\frac {b^{4} d^{4} - 8 \, a b^{3} d^{3} e + 8 \, a^{3} b d e^{3} - a^{4} e^{4} - 12 \, {\left (b^{4} d e^{3} - a b^{3} e^{4}\right )} x^{3} - 18 \, {\left (b^{4} d^{2} e^{2} - a^{2} b^{2} e^{4}\right )} x^{2} - 4 \, {\left (b^{4} d^{3} e + 6 \, a b^{3} d^{2} e^{2} - 6 \, a^{2} b^{2} d e^{3} - a^{3} b e^{4}\right )} x - 12 \, {\left (b^{4} e^{4} x^{4} + a^{2} b^{2} d^{2} e^{2} + 2 \, {\left (b^{4} d e^{3} + a b^{3} e^{4}\right )} x^{3} + {\left (b^{4} d^{2} e^{2} + 4 \, a b^{3} d e^{3} + a^{2} b^{2} e^{4}\right )} x^{2} + 2 \, {\left (a b^{3} d^{2} e^{2} + a^{2} b^{2} d e^{3}\right )} x\right )} \log \left (b x + a\right ) + 12 \, {\left (b^{4} e^{4} x^{4} + a^{2} b^{2} d^{2} e^{2} + 2 \, {\left (b^{4} d e^{3} + a b^{3} e^{4}\right )} x^{3} + {\left (b^{4} d^{2} e^{2} + 4 \, a b^{3} d e^{3} + a^{2} b^{2} e^{4}\right )} x^{2} + 2 \, {\left (a b^{3} d^{2} e^{2} + a^{2} b^{2} d e^{3}\right )} x\right )} \log \left (e x + d\right )}{2 \, {\left (a^{2} b^{5} d^{7} - 5 \, a^{3} b^{4} d^{6} e + 10 \, a^{4} b^{3} d^{5} e^{2} - 10 \, a^{5} b^{2} d^{4} e^{3} + 5 \, a^{6} b d^{3} e^{4} - a^{7} d^{2} e^{5} + {\left (b^{7} d^{5} e^{2} - 5 \, a b^{6} d^{4} e^{3} + 10 \, a^{2} b^{5} d^{3} e^{4} - 10 \, a^{3} b^{4} d^{2} e^{5} + 5 \, a^{4} b^{3} d e^{6} - a^{5} b^{2} e^{7}\right )} x^{4} + 2 \, {\left (b^{7} d^{6} e - 4 \, a b^{6} d^{5} e^{2} + 5 \, a^{2} b^{5} d^{4} e^{3} - 5 \, a^{4} b^{3} d^{2} e^{5} + 4 \, a^{5} b^{2} d e^{6} - a^{6} b e^{7}\right )} x^{3} + {\left (b^{7} d^{7} - a b^{6} d^{6} e - 9 \, a^{2} b^{5} d^{5} e^{2} + 25 \, a^{3} b^{4} d^{4} e^{3} - 25 \, a^{4} b^{3} d^{3} e^{4} + 9 \, a^{5} b^{2} d^{2} e^{5} + a^{6} b d e^{6} - a^{7} e^{7}\right )} x^{2} + 2 \, {\left (a b^{6} d^{7} - 4 \, a^{2} b^{5} d^{6} e + 5 \, a^{3} b^{4} d^{5} e^{2} - 5 \, a^{5} b^{2} d^{3} e^{4} + 4 \, a^{6} b d^{2} e^{5} - a^{7} d e^{6}\right )} x\right )}} \]
-1/2*(b^4*d^4 - 8*a*b^3*d^3*e + 8*a^3*b*d*e^3 - a^4*e^4 - 12*(b^4*d*e^3 - a*b^3*e^4)*x^3 - 18*(b^4*d^2*e^2 - a^2*b^2*e^4)*x^2 - 4*(b^4*d^3*e + 6*a*b ^3*d^2*e^2 - 6*a^2*b^2*d*e^3 - a^3*b*e^4)*x - 12*(b^4*e^4*x^4 + a^2*b^2*d^ 2*e^2 + 2*(b^4*d*e^3 + a*b^3*e^4)*x^3 + (b^4*d^2*e^2 + 4*a*b^3*d*e^3 + a^2 *b^2*e^4)*x^2 + 2*(a*b^3*d^2*e^2 + a^2*b^2*d*e^3)*x)*log(b*x + a) + 12*(b^ 4*e^4*x^4 + a^2*b^2*d^2*e^2 + 2*(b^4*d*e^3 + a*b^3*e^4)*x^3 + (b^4*d^2*e^2 + 4*a*b^3*d*e^3 + a^2*b^2*e^4)*x^2 + 2*(a*b^3*d^2*e^2 + a^2*b^2*d*e^3)*x) *log(e*x + d))/(a^2*b^5*d^7 - 5*a^3*b^4*d^6*e + 10*a^4*b^3*d^5*e^2 - 10*a^ 5*b^2*d^4*e^3 + 5*a^6*b*d^3*e^4 - a^7*d^2*e^5 + (b^7*d^5*e^2 - 5*a*b^6*d^4 *e^3 + 10*a^2*b^5*d^3*e^4 - 10*a^3*b^4*d^2*e^5 + 5*a^4*b^3*d*e^6 - a^5*b^2 *e^7)*x^4 + 2*(b^7*d^6*e - 4*a*b^6*d^5*e^2 + 5*a^2*b^5*d^4*e^3 - 5*a^4*b^3 *d^2*e^5 + 4*a^5*b^2*d*e^6 - a^6*b*e^7)*x^3 + (b^7*d^7 - a*b^6*d^6*e - 9*a ^2*b^5*d^5*e^2 + 25*a^3*b^4*d^4*e^3 - 25*a^4*b^3*d^3*e^4 + 9*a^5*b^2*d^2*e ^5 + a^6*b*d*e^6 - a^7*e^7)*x^2 + 2*(a*b^6*d^7 - 4*a^2*b^5*d^6*e + 5*a^3*b ^4*d^5*e^2 - 5*a^5*b^2*d^3*e^4 + 4*a^6*b*d^2*e^5 - a^7*d*e^6)*x)
\[ \int \frac {1}{(d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\int \frac {1}{\left (d + e x\right )^{3} \left (\left (a + b x\right )^{2}\right )^{\frac {3}{2}}}\, dx \]
Exception generated. \[ \int \frac {1}{(d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\text {Exception raised: ValueError} \]
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(a*e-b*d>0)', see `assume?` for m ore detail
Leaf count of result is larger than twice the leaf count of optimal. 447 vs. \(2 (206) = 412\).
Time = 0.28 (sec) , antiderivative size = 447, normalized size of antiderivative = 1.62 \[ \int \frac {1}{(d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\frac {6 \, b^{3} e^{2} \log \left ({\left | b x + a \right |}\right )}{b^{6} d^{5} \mathrm {sgn}\left (b x + a\right ) - 5 \, a b^{5} d^{4} e \mathrm {sgn}\left (b x + a\right ) + 10 \, a^{2} b^{4} d^{3} e^{2} \mathrm {sgn}\left (b x + a\right ) - 10 \, a^{3} b^{3} d^{2} e^{3} \mathrm {sgn}\left (b x + a\right ) + 5 \, a^{4} b^{2} d e^{4} \mathrm {sgn}\left (b x + a\right ) - a^{5} b e^{5} \mathrm {sgn}\left (b x + a\right )} - \frac {6 \, b^{2} e^{3} \log \left ({\left | e x + d \right |}\right )}{b^{5} d^{5} e \mathrm {sgn}\left (b x + a\right ) - 5 \, a b^{4} d^{4} e^{2} \mathrm {sgn}\left (b x + a\right ) + 10 \, a^{2} b^{3} d^{3} e^{3} \mathrm {sgn}\left (b x + a\right ) - 10 \, a^{3} b^{2} d^{2} e^{4} \mathrm {sgn}\left (b x + a\right ) + 5 \, a^{4} b d e^{5} \mathrm {sgn}\left (b x + a\right ) - a^{5} e^{6} \mathrm {sgn}\left (b x + a\right )} + \frac {12 \, b^{3} e^{3} x^{3} + 18 \, b^{3} d e^{2} x^{2} + 18 \, a b^{2} e^{3} x^{2} + 4 \, b^{3} d^{2} e x + 28 \, a b^{2} d e^{2} x + 4 \, a^{2} b e^{3} x - b^{3} d^{3} + 7 \, a b^{2} d^{2} e + 7 \, a^{2} b d e^{2} - a^{3} e^{3}}{2 \, {\left (b^{4} d^{4} \mathrm {sgn}\left (b x + a\right ) - 4 \, a b^{3} d^{3} e \mathrm {sgn}\left (b x + a\right ) + 6 \, a^{2} b^{2} d^{2} e^{2} \mathrm {sgn}\left (b x + a\right ) - 4 \, a^{3} b d e^{3} \mathrm {sgn}\left (b x + a\right ) + a^{4} e^{4} \mathrm {sgn}\left (b x + a\right )\right )} {\left (b e x^{2} + b d x + a e x + a d\right )}^{2}} \]
6*b^3*e^2*log(abs(b*x + a))/(b^6*d^5*sgn(b*x + a) - 5*a*b^5*d^4*e*sgn(b*x + a) + 10*a^2*b^4*d^3*e^2*sgn(b*x + a) - 10*a^3*b^3*d^2*e^3*sgn(b*x + a) + 5*a^4*b^2*d*e^4*sgn(b*x + a) - a^5*b*e^5*sgn(b*x + a)) - 6*b^2*e^3*log(ab s(e*x + d))/(b^5*d^5*e*sgn(b*x + a) - 5*a*b^4*d^4*e^2*sgn(b*x + a) + 10*a^ 2*b^3*d^3*e^3*sgn(b*x + a) - 10*a^3*b^2*d^2*e^4*sgn(b*x + a) + 5*a^4*b*d*e ^5*sgn(b*x + a) - a^5*e^6*sgn(b*x + a)) + 1/2*(12*b^3*e^3*x^3 + 18*b^3*d*e ^2*x^2 + 18*a*b^2*e^3*x^2 + 4*b^3*d^2*e*x + 28*a*b^2*d*e^2*x + 4*a^2*b*e^3 *x - b^3*d^3 + 7*a*b^2*d^2*e + 7*a^2*b*d*e^2 - a^3*e^3)/((b^4*d^4*sgn(b*x + a) - 4*a*b^3*d^3*e*sgn(b*x + a) + 6*a^2*b^2*d^2*e^2*sgn(b*x + a) - 4*a^3 *b*d*e^3*sgn(b*x + a) + a^4*e^4*sgn(b*x + a))*(b*e*x^2 + b*d*x + a*e*x + a *d)^2)
Timed out. \[ \int \frac {1}{(d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\int \frac {1}{{\left (d+e\,x\right )}^3\,{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{3/2}} \,d x \]